a square has an area of 36 and one side that lies along the line y=3. what could be the location of one of the vertices of this shape? a) (9, 4) b) (-5, -3) c) (6, 5) d) (3, 6)

the distance between point a and point b is 6 units

its totaly b

your welcome btw

i suppose it should be (y=2x-5)

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92