Three-fourths of the water leaked out of a full aquarium tank. and 15 gallons of water was left. After the leak was fixed, 10 gallons of water was added to the
aquarium tank.
4) How many gallons of water can the aquarium tank hold when it is full?
5) How full was the aquarium tank after the 10 gallons of water was added?
6) How much more water would have to be added to fill the aquarium tank?

4) 60 gallons    5) 25 gallons    6) 35 gallons

Step-by-step explanation:

If three-fourths of the water in the tank leaked out of the full aquarium tank then one-fourths will be left.

so if the leftover was 15 gallons then 1/4 of a number has to equal 15 gallons.

We could represent that by the equation.

1/4 * x = 15

0.25x = 15

x=  60    

4) which means the aquarium tank can hold 60 gallons of water when it is full.

5) If 15 gallons of water was left after the leaking and then they added 10 more gallons of water then 15 + 10 = 25   which means the aquarium was 25 gallon full.

6) If they are 25 gallons in the water now and we need to add some amount of water to get to 60 gallons of water then we will subtract  25 from 60 find how much water needs to be added.

So  60 -25 = 35   which means 35  gallons needs to be added.  

the circle one

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0