The solutions of the equations -xΒ² + 4x +3 = 0 are
A. (x = -3) and (x = -1)
B. (x = 1) and (x...
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Mathematics, 03.08.2020 14:01 partykidjeremsih
The solutions of the equations -xΒ² + 4x +3 = 0 are
A. (x = -3) and (x = -1)
B. (x = 1) and (x = 3)
C. (x = -2 -β7) and (x = -2 + β7)
D. (x = 2 -β7) and (x = 2 + β7)
can someone explain this pls
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