ASAP I really need help...

304(pi) g

Step-by-step explanation:

First we find the volume of the hollow ball. Then we find the mass using the volume and density.

Let R = exterior radius = 3 cm

Let r = interior radius = 2 cm

volume = exterior volume - interior volume

volume = (4/3)(pi)R^3 - (4/3)(pi)r^3

volume = (4/3)(pi)(R^3 - r^3)

volume = (4/3)(pi)(3^3 - 2^3) cm^3

volume = (4/3)(pi)(27 - 8) cm^3

volume = (76/3)pi cm^3

Now we use the density and the volume to find the mass.

density = mass/volume

mass = density * volume

mass = 12 g/cm^3 * (76/3)pi cm^3

mass = 304(pi) g

304(pi) g

m=(76π/3 )(12)=304πg

Step-by-step explanation:

volume of sphere=(4πr³)/3

V=4π(2)³/3=32π/3 of the interior

V of exterior=4π(3)³/3=36π

Volume of the whole metal =108π/332π/3=76π/3=25 1/3 π

m=V*D ( volume * density)=

m=(76π/3 )(12)=304πg

what is the original number? you forgot to add it.