An automotive plant makes the Quartz and the Pacer. The plant has a maximum production capacity of 1200 cars per week, and they can make at most 600 Quartz cars and 800 Pacers each week. If the profit on a Quartz is $500 and the profit on a Pacer is $800, find how many of each type of car the plant should produce.

x=400 and y=800

Step-by-step explanation:

let x be the Quartez and y is Pacer

x+y≤1200 ( maximum production capacity of 1200 cars per week)

0≤x≤600

0≤y≤800

profit : 500x+800y

at a point : x=0 y=800

profit=500x+800y ⇒ 500(0)+800(800)=640000

profit= 500(600)+0=300000 wen x=600(max), y=0

Profit=500(600)+800(600)= 780000

profit =500(400)+800(800)=840000 this is the max profit when

x=400 and y=800

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!