A group of patients select from among 38 numbers, with 18 odd numbers (black) and 18 even numbers (red), as well as 0 and 00 (which are green). If a doctor pays $7 that the outcome is an odd
number, the probability of losing the $7 is 20/38 and the probability of winning $14 (for a net gain of
only $7, given you already paid $7) is 18/38
If a doctor pays $7 that the outcome is an odd number, how would you figure out what is the doctors
expected value is?

$2.95

Step-by-step explanation:

Given: Probability of losing the $7 =

Probability of winning $14  =

Then, the expected value = (- $7)  x ( Probability of losing the $7) + $14 x(Probability of winning $14)

=

=

=

∴ If a doctor pays $7 that the outcome is an odd number, the doctor's

expected value is $2.95.

12/11c

or

12

c

11

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this