Determine the critical value for a 98% confidence interval when the sample size is 12 for the t ‑distribution. Enter the positive critical value rounded to 3 decimal places.

+2.718

Step-by-step explanation:

from the question,

the sample size is 12

therefore the degree of freedom,

df = 12 - 1

= 11

alpha = 1 - 0.98

= 0.02

this is because the confidence level is 98%

under the t distribution table, a degree of freedom of 11 and 0.02 alpha level = 2.718

the critical value t* = 2.718

I hope this helps!

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