List the first 5 terms of the sequence -3n -2.

-5,-8,-11,-14,-17

Step-by-step explanation:

-3n -2

n=1   -3(1) -2 = -3-2 = -5

n=2   -3(2) -2 = -6-2 = -8

n=3   -3(3) -2 = -9-2 = -11

n=4   -3(4) -2 = -12-2 = -14

n=5   -3(5) -2 = -15-2 = -17

We can substitute n with each term in order.

First Term:

-3(1) - 2

-3 - 2

-5

Second Term:

-3(2) - 2

-6 - 2

-8

Third Term:

-3(3) - 2

-9 - 2

-11

Fourth Term:

-3(4) - 2

-12 - 2

-14

Fifth Term:

-3(5) - 2

-15 - 2

-17

Therefore, the sequence is -5, -8, -11, - 14, -17

Best of Luck!

step-by-step explan mxfcg'k; uafwgzfgjhklhgation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.