A 5cm x 11cm rectangle sits inside a circle with radius of 12 cm. What is the area of the shaded region? Round your final answer to the nearest hundredth.

Step-by-step explanation:

area of shaded region = 3168/7 - 55 = 397.5cm^2 (app)= 0.397cm^2 ( since we have to round to nearest hundredth

The answer is

Step-by-step explanation:

To find the area of the shaded area first find the area of both the rectangle and the circle and subtract the smaller one from the larger one.

that's

For the rectangle

Area of rectangle = length × width

From the question

length = 5cm

width = 11 cm

So we have

Area of rectangle = 5cm × 11cm = 55cm²

For the circle

Area of a circle = πr²

where r is the radius

From the question

r = 12 cm

Area of circle = π (12)²

= 144π

= 452.40 cm²

Area of shaded figure

Since the area of the rectangle is smaller than that of the circle we subtract the area of the rectangle from the circle

That's

452.40 cm² - 55cm²

= 397.40 cm² to the nearest hundredth

Hope this helps you

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!