PLEASE HELP ME WITH THESE FIVE QUESTION ASPA 1.) y = x − 1 y = -2x + 5 (1, 1) (2, 1) There are infinite solutions. There are no solutions. 2.) y = -x − 4 4y − 2x = 8 (-6, -2) (-4, 0) There are infinite solutions. There are no solutions. 3.)2x − 3y = -5 y = 2 + x y = -1. y = -3. y = 1. y = 3. 4.)2x − 3y = -5 y = 2 + x x = -1. x = -3. x = 1. x = 3. 5.) 3y − 2 = x -2x − y = -17 (7, 3) (7, 8) (1, 7) (1, -7)

25

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral