A committee has members. There are members that currently serve as the board's . Each member is equally likely to serve in any of the positions. members are randomly selected and assigned to be the new . What is the probability of randomly selecting the members who currently hold the positions of and reassigning them to their current positions? The probability is nothing.

Complete Question

A committee has six members. There are three members that currently serve as the board's chairman comma vice chairman comma and treasurer . Each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman comma vice chairman comma and treasurer . What is the probability of randomly selecting the three members who currently hold the positions of chairman comma vice chairman comma and treasurer and reassigning them to their current positions?

The probability is ?

The probability is

Step-by-step explanation:

From the question we are told that

       The total number of members is  n = 6  

       The  number of member to be selected is  r =  3  

Generally the number of ways of selecting 3 members from 6  is mathematically evaluated as

=>      

=>        

=>      

=>        

Now the number of ways of selecting the 3 members who currently hold the position is  n  = 1

  So the probability is mathematically represented as

substituting values

8121 because

130,000 divided by 16 is 8121

correct answer:

i^31 = -i