For functions f(x)=2x^2−4x+3 and g(x)=x^2−2x−6, find a. (f+g)(x) b. (f+g)(3).

a) 3x^2-6x-3

b) 6

Step-by-step explanation:

f(x)=2x^2−4x+3

g(x)=x^2−2x−6

a)  (f+g)(x) = (2x^2−4x+3) + (x^2−2x−6)

             collect like terms

   (f+g)(x) = 2x^2+x^2-4x-2x+3-6

   (f+g)(x) = 3x^2-6x-3

b) (f+g)(3). This implies that x=3

  recall (f+g)(3) = 3x^2-6x-3

   (f+g)(3) = 3(3)^2-6(3)-3 = 27-18-3

   (f+g)(3) = 27-21 =6

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

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step-by-step explanation: