You are given 7 to 1 odds against rolling a sum of 6 with the roll of two fair dice, meaning you win $7 if you succeed and you lose $1 if you fail. Find the expected value (to you) of the game.

The expected value of the game is $0.33.

Step-by-step explanation:

There are N = 36 outcomes of rolling two 6-sided fair dice.

The sample for the sum of two numbers to be 7 is:

S = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2) and (6, 1)}

n (S) = 6

It is provided that there is a 7 to 1 odds against rolling a sum of 6 with the roll of two fair dice.

That is, you win $7 if you succeed and you lose $1 if you fail.

Compute the expected value of the game as follows:

Thus, the expected value of the game is $0.33.

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

hi there

the slope is 1/3.

this is because from the y-intercept, you go up one, and you go to the right three, to get to the next exact point on the graph. this is known at the “rise over run.”

p.s. (if you need it).your y-intercept is -2, because that is the point on the graph where the line crosses the y-axis.

hope that : )