Part I: Binomial Probability Histograms The frame below initially shows a binomial probability histogram with parameters n = 5 and p = 50%. Find one of the bins for which the normal approximation and the binomial probability differ most. Problem 1 One of the bins for which the binomial probability differs most from the normal approximation is the bin centered at (type an integer) (Q1) , where the absolute value of the difference in areas is (Q2) Change the probability p of success to 32%, and find the bin for which the difference between the normal approximation and the binomial probability is largest. Problem 2 For p= 32%, the absolute value of the largest difference between the area of one bin in the binomial probability histogram and the normal approximation is (Q3)

for any of you who need the translation here it is

step-by-step explanation:

find the angular size of the equatorial radius of the earth, if the horizontal parallax of the sun

answer: hey there,

the answer you are looking for is a..

hope this you!

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)