Help me out :O What is the volume of three cubes, each with a side length of fraction 1 over 3 foot? V = s3, where s is the side length.

3. 1/9 feet^3

Step-by-step explanation:

First, find the volume of one cube.

The volume of a cube can be found using the following formula:

V=s^3

We know that s, the side length is 1/3 feet. Therefore, we can substitute 1/3 ft in for s.

V= (1/3 ft)^3

Evaluate the exponent.

1/3 ft^3

=1/3 ft * 1/3 ft* 1/3 ft

=1/9 ft^2*1/3 ft

= 1/27 ft^3

V= 1/27 ft^3

Now find the volume of 3 cubes. We know the volume of one cube is 1/27 ft^3, therefore we can multiply 1/27 ft^3 by 3.

1/27 ft^3 * 3

Multiply 1/27 and 3.

1/27 * 3/1

=(1*3)/(27*1)

=3/27

=1/9

V= 1/9 ft^3

The volume of 3 cubes is 1/9 cubic feet, and choice 3 is correct.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.