Explain why f(x) = x^2-x-6/x^2-9 is not continuous at x = 3.

See Explanation

Step-by-step explanation:

Given

Required

Why is the function not continuous at x = 3

First substitute 3 for x at the denominator

Factorize the numerator and the denominator

Divide the numerator and denominator by (x - 3)

Substitute 3 for x

Because is defined when x = 3;

Then the function is continuous

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17