Plz help me 3y+x=7
4x-2y=0

x = 1

y = 2

Step-by-step explanation:

3y +   x = 7       first equation

-2y + 4x  = 0      second equation

multiplying by -4 the first equatión

-4(3y + x = 7)

-4*3y -4*x = -4*7

-12y -4x = - 28

and sum the second equation:

-12y -  4x = -28

- 2y - 4x  =  0

-14y   -  0  =  -28

-14y = -28

y = -28/-14

y = 2

from the first equation:

3y + x = 7

3*2 + x = 7

6 + x = 7

x = 7 - 6

x = 1

Check:

from the second equation:

4x - 2y = 0

4*1 - 2*2 = 0

4 - 4 = 0

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.