Solve 2x^2 +3x -7= x^2 +5x + 39 for x.

a. x= -6+ square root 82
b. x= -6+2 square root 17
c. x= 1+ square root 33
d. x= 1+ square root 47

2x^2 + 3x - 7 = x^2 + 5x + 39 =
2x^2 - x^2 + 3x - 5x - 7 - 39 = 0
x^2 - 2x - 46 = 0

x = (-b (+-) sqrt b^2 - 4ac) / 2a
x = (-(-2) (+-) sqrt -2^2 - 4(1)(-46) / 2(1)
x = 2 (+-) sqrt 4 + 184) / 2
x = 2 (+-) sqrt 188) / 2
x = 1 (+-) sqrt 47

The answer is 10 bud