Find the equation of the tangent line to the graph of f(x) = x2 – 8 at the point (4,8).

f'(4) =  8   tangent of f(x) at (4,8)

Step-by-step explanation:

f(x) = x^2 - 8

f'(x) = 2x

f'(4) = 2*4 = 8   tangent of f(x) at (4,8)

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2