Please help! I got 14 but it says it's incorrect! Find the maximum number of real zeros of the polynomial. f(x)=2x^(6)-3x^(3)+1-2x^(5)

There are two or zero positive solutions and zero negative roots (zeros).

Step-by-step explanation:

Use Descartes' Rule of Signs to determine the number of real zeros of

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

-14 is the answer

hope this : ))