The value of y varies inversely as the square of x, and y = 16, when x = 3. Find the value of 2 when y = 1

The answer is

Step-by-step explanation:

The above variation is written as

where k is the constant of variation

when y = 16

x = 3

k = yx²

k = 16(3)²

k = 16 × 9

k = 144

The formula for the variation is

when y = 1

We have

Cross multiply

x² = 144

Find the square root of both sides

x = √144

x = 12

Hope this helps you

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step-by-step explanation: