In a small town, there are 4 times as many left-handed males as there are left-handed females, and there are 3 times as many right-handed females as there are right-handed males. There are a total of 204 males and 348 females in the town. Let x represent the number of left-handed females, and let y represent the number of right-handed males. Write a system of equations to represent the situation. What is the value of x, the number of left-handed females? A. 6 B.24 C. 96 D. 108

24

Expenation:  

Left handed females = x

right handed females = 348 - x

right handed males = y

left handed males = 204 - y

204 - y = 4x

348 - x = 3y

4x + y = 204  . . . . . . . (1)

x + 3y = 348  . . . . . . . (2)

From (2),  x = 348 - 3y

subsituting for x in (1), we have

4(348 - 3y) + y = 204

1392 - 12y + y = 204

12y - y = 1392 - 204

11y = 1188

y = 1188/11 = 108

x = 348 - 3y = 348 - 3(108) = 348 - 324 = 24

24

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i got it right

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