The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. An article gave the accompanying sample observations on breakdown voltage (kV) of a particular circuit under certain conditions. 62 51 54 57 42 53 56 61 59 64 51 54 64 62 51 68
54 56 58 51 55 51 56 55 46 55 53 54 52 48 47 56
58 49 63 58 57 56 54 59 53 53 50 55 60 50 56 59
a) Construct a boxplot of the data and comment on interesting features.
b) Calculate and interpret a 95% Confidence Interval for true average breakdown voltage μ. Does it appeas that μ has been precisely estimated? Explain.
c) Suppose the investigator believes that virtually all values of breakdown voltage are between 40 and 70. What sample size would be appropriate for the 95% Confidence Interval to have a width of 2kV (so that μ is estimated to within 1 kV with 95% confidence?)

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

he kicked it up? is this the answer ?

step-by-step explanation:

i love jeffery and believe there is truth in tati and james' answers

step-by-step explanation:

yes i have heard the tea

i believe both

no, tati didnt over exaggerate

james might might idk and tbh dont rly care

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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