In an isolated environment, a disease spreads at a rate proportional to the product of the infected and non-infected populations. Let I(t) denote the number of infected individuals. Suppose that the total population is 2000, the proportionality constant is 0.0001, and that 1% of the population is infected at time t-0, write down the intial value problem and the solution I(t). dI/dt =
1(0) =
I(t) =
symbolic formatting help

The required expressions are presented below:

After reading the statement, we obtain the following differential equation:

(1)

Where:

Then, we solve the expression by variable separation and partial fraction integration:

, where (2, 3)

Note - Please notice that is the initial infected population.

If we know that , and , then we have the following set of expressions:

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3,750 deer

step-by-step explanation:

1,500 is 15 times larger than 100

lets make 250 15 times larger.

3750 deer