Which expression can you simplify by combining like terms? 12b2+4ab−3ba−6 17a2−6b2a+4ba−9 5b2−5a2+8a−b 14a2+6ab−3b−3a

12b^2+4ab−3ba−6

Step-by-step explanation:

12b2+4ab−3ba−6

The two middle terms are like terms, the order in which you multiply does not matter ab =ba

12 b^2 +4ab -3ab -6

12 b^2 +ab -6

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

the answer to this is a. a^2 + b^2 = c^2