What are the zeros of the quadratic function f (x) = 2x^2 -10x-3?

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

Step-by-step explanation:

1. Need to factor or can use the quadratic formula

2x^2-10x-3=0

a=2, b=-10, c=-3

[-b+-sqrt(b^2-4*a*c)]/(2*a)

[10+-sqrt(100-4*(-200)]/4

[10+- sqrt(300)]/4

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

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step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: