the number of new cars purchased can be modeled by the equation, c=20t^2+135t+3050, where C is the number if new cars and t=0 corresponds to the number of new cars purchased in 1998. in what year will the number of new cars purchased reach 15,000

2019

Step-by-step explanation:

first you should change the statement into quadratic equation and replace c with 15000.

c=20t^2+135t+3050.

15000=20t^2+135t+3050

15000-3050=20t^2+135t

11950=20t^2+135t. then write the equation in standard quadratic form.

20t^2+135t-11950=0. after this you got 4 ways of solving the quadratic equation but I am just gone using quadratic formula:

-b+ - √b^2-4ac. a,b and C stand for the

2a.the coefficients

-135+ - √((135)^2-4(20)(-11950))

2(20)

-135+ - √(974225))

)) 40

-135 - 987 or -135+ 987

40.40

-1122/40. or 852/40

- 28.05or. 21.3

in this case we have to answer but time cannot be negative we take value 21.3(it is the approximate value)

so we add 21.3 to 1998 to find the year

>>21.3 + 1998 = 2019.3 but we write it as 2019 instead of 2019.3

i would need to see the dot plot : )

none cuz there are no "following statements" regarding the question

step-by-step explanation: