Solve the following quadratic equation 6x2 – 7x = 20

Step-by-step explanation:

6x² - 7x - 20 = 0

Using method of factorization

Rewrite - 7x as a difference

That's

6x² + 8x - 15x - 20 = 0

Factor the expression

That's

2x( 3x + 4) - 5( 3x + 4) = 0

Which is

(2x - 5) (3x + 4) = 0

2x - 5 = 0

2x = 5

Divide both sides by 2

x = 5/2

3x + 4 = 0

3x = - 4

Divide both sides by 3

x = -4/3

Hope this helps you

x = -4/3 or x = 5/2

Step-by-step explanation:

given  6x² - 7x = 20

There are several ways to solve this, we'll choose to use the quadratic formula:

Recall that for a quadratic equation ax² + bx + c = 0

x = [ -b±√(b²-4ac)  ] / 2a

in our case, if we rearrange the equation, we will get:

6x² - 7x -20 = 0

comparing this with the general form of the quadratic equation above, we can see that

a = 6, b = -7 and c = -20

substituting these into the equation:

x = [ -b±√(b²-4ac)  ] / 2a

x = { -(-7)±√[(-7)²-4(6)(-20)] } / 2(6)

x = -4/3 or x = 5/2

what is the question here

step-by-step explanation:

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