How can you solve this type of linear equation
f(x) = cube root(x+8)?

all it means is function 3

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

the equation is not included but the answer is (1.50, 2.00, 2.75)

step-by-step explanation: