Mathematics, 27.07.2020 01:01 dani595

Help I don't understand

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Answer from: tristanortonubca

x = 9.9 in.

2 of the same type of triangle = 1 square

To find x, you have to remember that a square is made from two right triangles combined. In this photo, we can see that the length and width of the triangle have the same value (the two sides that point up and to the right), so that means if we multiply the area by two, then we get the area of a square or two of the same triangle's area.

Step 1:

To find the area of the square/two triangles, multiply the area by two.

49*2=98

98 is the area of the square.

Step 2:

Now we have to find the square of 98 (find two numbers that are the same that multiply to 98).

$\sqrt{98}$

When we solve this square, we find out that it is not a perfect number. So:

$\sqrt{98} =\\9.89949$

That is just an estimate of x, so when we round to the nearest tenth, we get 9.9.

To check our answer, multiply 9.9 by 9.9 and we get 98.01, but since we rounded our answer, 98.01 is correct. If we round that to 98 and divide by 2, we get our original area of one triangle, 49.

x = 9.9

Answer from: LunaShiner

9.9

Step-by-step explanation:

Well let's work backwards.

If the area is 49 then we do 49*2 because after doing b*h you divide by 2.

So 49*2 = 98.

If the b and h is the same then we find the square root of 98,

which is 9.899494937.

Thus,

the answer is 9.9 rounded to the nearest tenth.

Hope this helps :)

Answer from: Quest

so what is the question

step-by-step explanation:

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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