Problem solving: Janine is 7 years younger than Lucy and 4 years older than Samantha. The average of their ages is 16. How old is:
a. Janine?
b. Samantha?
c. Lucy?

Janine=12.6(repeating) Samantha=15.6(repeating) Lucy=19.6(repeating)

Step-by-step explanation:

Lets concentrate on one person, Janine.

Janine = Lucy - 7

Janine = Samantha - 3

If the averae of the 3 people's ages is 16, then we should multiple that by three to get 48, the number of their ages combined.

Janine + Lucy + Samantha = 48

The differences between Janine to Lucy and Janine to Samantha combined is 10, so we can subtract that from 48 to get 38, which is 3 times Janines age.

38/3=12.6(repeating)

That is Janine's age. We can use that to find both Lucy's and Samantha's ages respectively by using their equations. Lucy's is 19.6(repeating) and Samantha's is 15.6(repeating). I hope you can give me brainliest, and that this helped!

one set of data has more variation than the other. hope this !