Use the tables below to find (p − q)(2). A 2-column table has 3 rows. The first column is labeled x with entries 4, 2, negative 3. The second column is labeled p (x) with entries negative 1, 3, 2. A 2-column table has 3 rows. The first column is labeled x with entries 4, 2, negative 3. The second column is labeled q (x) with entries 1, negative 2, 5.

(p – q)(2) =

32

step-by-step explanation:

i suppose it should be (y=2x-5)

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: