Suppose that E and F are two events and that P(E and F) = 0.2 and P(E) = 0.4. What is P(F/E)

The conditional probability is given by

P(F|E) = P(E and F)/P(E)

P(F|E) = 0.2/0.4

P(F|E) = 0.5

P(F|E) = 50%

Step-by-step explanation:

Recall that the conditional probability is given by

∵ P(B | A) = P(A and B)/P(A)

For the given case,

P(F|E) = P(E and F)/P(E)

Where P(F|E) is the probability of event F occurring given that event E has occurred.

The probability of event E and F is given as

P(E and F) = 0.2

The probability of event E is given as

P(E) = 0.4

So, the conditional probability is

P(F|E) = P(E and F)/P(E)

P(F|E) = 0.2/0.4

P(F|E) = 0.5

P(F|E) = 50%

the answer

b. they are parallel and will never intersect.

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!