In ΔJKL, solve for x. Please Help! ASAP! 45 points and brianliest! Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle J measures 27 degrees. A) 66.73 B) 74.89 C) 15.44 D) 38.16

A.

Step-by-step explanation:

In this question we are using SohCahToa.

Looking from the side of the 27 degree angle, we have a value for the opposite side, and we are looking for x which is on the hypotenuse side. In this case you use Tan.

So the equation is tan(27)(34/x)

tan(27) is .509 than you have to do 34/.509 to solve for x.

And x is 66.728

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.