Mathematics, 26.07.2020 16:01 shadowangel84
The quadratic 4x^2+2x-1 can be written in the form a(x+b)^2+c, where a, b, and c are constants. What is a+b+c?
Answers: 3
![4x^2+2x-1=4(x^2+\dfrac{2}{4}x)-1=4[(x+\dfrac{1}{4})^2-\dfrac{1}{4^2}]-1](/tpl/images/0713/4546/ac924.png)
![4x^2+2x-1=4[(x+\dfrac{1}{4})^2-\dfrac{1}{4^2}]-1=4(x+\dfrac{1}{4})^2-\dfrac{1}{4}-1\\\\=4(x+\dfrac{1}{4})^2-\dfrac{1+4}{4}=\boxed{4(x+\dfrac{1}{4})^2-\dfrac{5}{4}}](/tpl/images/0713/4546/bb851.png)
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The quadratic 4x^2+2x-1 can be written in the form a(x+b)^2+c, where a, b, and c are constants. What...
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