A plane headed due south is traveling with an airspeed of 160 miles per hour. The wind currents are moving with constant speed in the direction
30°. If the ground speed of the plane is 80 miles per hour, what is its true
course?

60 °

Step-by-step explanation:

Applying the law of sine we have the following:

160 / Sin B = 80 / Sin 30 °

We solve for B and we have:

160 / Sin B = 80 / 0.5

160 / Sin B = 160

Without B = 160/160

B = Arc Sin (1)

B = 90 °

Now to calculate the other angle (true

 course) would be:

A = 180 ° - (B + C)

A = 180 ° - (90 ° + 30 °)

A = 60 °

That is to say that true course is 60 °

step-by-step explanation:

it's is b