The function g(x) is graphed. On a coordinate plane, a curved line enters the plane at point (negative 2.3, 5), crosses the x- and y-axis at (0, 0), and leaves the plane at point (2.3, 5).

Which statements about the function are true? Choose three options.

g of 1 = negative 1
g of 0 = 0
g of 4 = -2
g of 1 = 1
g of negative 1 = 1

g(1) = 1

g(0) = 0

g(-1) = 1

Step-by-step explanation:

The graph is missing, so the only data that we have is:

The curve pass through the point (-2.3, 5), the point (0, 0) and the point (2.3 ,5)

remember that a point is (x, y), and this is related to the function as:

f(x) = y.

So we can think that this is an even function because: g(-2.3) = g(2.3).

Now, without looking at the graph, the only statement that we know that is true is:

g(0) = 0, because we know that the function passes through the point (0,0)

Now, the other only possible correct options are:

g(-1) = 1

g(1) = 1

first: because our function is even, so g(1) = g(-1)

Second, we know that the function meets the x-axis at the point (0,0) so we can not have any negative value for y in the range, so the options:

g(1) = -1

g(4) = -2

must be discarded, then the only possible correct options are:

g(1) = 1

g(0) = 0

g(-1) = 1