If a(x) = 3x + 1 and b(x) = sqrt x-4 what is the domain of (b•a)(x)

[4, infinity)

Step-by-step explanation:

(b·a)(x) = (sqrt(x - 4)·(3x + 1).  The domain of 3x + 1 is "all real numbers," but the presence of the sqrt function limits the input to (b·a)(x) to [4, infinity); recall that the argument of the sqrt function must be zero or greater.

i believe so, according to my "strange" way of figuring out weird math problems like this.

hd extra 3-7 x d en is the answer