A large rectangle has side lengths of 8 meters and 6 meters. A smaller rectangle with side lengths of 4 meters and 2 meters is cut out of the large rectangle. What is the area of the remaining part of the large rectangle?

16m²

Step-by-step explanation:

A large rectangle has side lengths of 8 meters and 6 meters. This means that the area of the large rectangle will be:

= 8m × 6m

= 48m²

A smaller rectangle with side lengths of 4 meters and 2 meters is cut out of the large rectangle. Then, the area of the smaller rectangle will be:

= 4m × 2m

= 8m²

Since the smaller rectangle with side lengths of 4 meters and 2 meters is cut out of the large rectangle whose length is 8, meters and 6 meters, the remaining part of the rectangle will have length of (8m - 4m) = 4m and (6m - 2m) = 4m.

Area of the remaining part of the large rectangle will be:

= 4m × 4m

= 16m²

how am i supposed to answer

step-by-step explanation: