I=(a, d,f) H=(bcc, g)
Find the intersection of I and H.
Find the union of I and H.
Write your answers using set notation (in roster form).

Step-by-step explanation:

I = {a,d,f}

H = {bcc,g}

Intersection of I & H contains elements present in both I and H.

Since there are no common elements, the intersection is a null set, or

I intersect H = { }

The union of I and H contains elements present in either I or H, without repetitions (order is not important in the roster form of set notation)

I union H = {a,d,f,bcc,g}

x/3-10=8

x/3=18

x=48

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!