Mathematics, 24.07.2020 21:01 SpittingFatLama
Which of the following equations have infinitely many solutions? β6x+35=β6xβ35minus, 6, x, plus, 35, equals, minus, 6, x, minus, 35 (Choice B) B 6x+35=-6x-356x+35=β6xβ356, x, plus, 35, equals, minus, 6, x, minus, 35 (Choice C) C -6x+35=-6x+35β6x+35=β6x+35minus, 6, x, plus, 35, equals, minus, 6, x, plus, 35 (Choice D) D 6x+35=-6x+356x+35=β6x+35
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Which of the following equations have infinitely many solutions? β6x+35=β6xβ35minus, 6, x, plus, 35,...
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