If 2+3=1 , 4+5=63 , 6+8=48 , then ,3+7=??

3+7 = 3

Step-by-step explanation:

Given question is based on reasoning:

2+3=1

2+3 = 5 and 5 × (2) first digit = 10, digit place reverse = 01

Similarly

4+5=63

4+5 = 9 and 9 × (4) first digit = 36, digit place reverse = 63

6+8=48

6+8 = 14 and 14 × (6) first digit = 84, digit place reverse = 48

So,

3+7=

3+7 = 10 and 10 × (3) first digit = 30, digit place reverse = 03

Therefore, 3+7 = 3

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: