Find the product of the following. i) –5a2bc, 6ab, 8abc2
ii) –3x2y and (5y – xy)
iii) x2y2z2 and (xy – yz + zx)
iv) (p+6)and (q–7)
v) (2x+7)and(x2 –5x+6) vii) (x + y + 5) and (2x – 2y – 3)
PLEASE I NEED THE ANSWER NOW

i)  -240

ii) -15x²y² + 3x³y²

iii)x³y³z³ - x²y³z³ + x³y²z³

iv) pq -7p+6q-42

v)9x²-33x +42

vii)  2x² - 2y² + 7x -13y - 15

Step-by-step explanation:

To find product here means to multiply the algebraic expressions together

i) (–5a²bc)×(6ab)×(8abc² )

multiply like terms together

= -240

ii) (–3x²y) ×(5y – xy)

(–3x²y)×(5y) –  (–3x²y) ×(xy)

multiply like terms together

multiplication of same sign gives +, while that of opposite sign gives -

= -15x²y² + 3x³y²

iii) (x²y²z²) ×(xy – yz + zx)

(x²y²z²)×(xy) – (yz)× (x²y²z²) + (zx)  ×(x²y²z²)

multiply like terms together

multiplication of same sign gives +, while that of opposite sign gives -

= x³y³z³ - x²y³z³ + x³y²z³

iv) (p+6)and (q–7)

p(q–7)  +6(q–7)

multiply like terms together

multiplication of same sign gives +, while that of opposite sign gives -

= pq -7p+6q-42

v) (2x+7)and(x² –5x+6)

multiply like terms together

multiplication of same sign gives +, while that of opposite sign gives -

= 2x² -10x+12x+7x²-35x+42

collect like terms

= 9x²-33x +42

vii) (x + y + 5) and (2x – 2y – 3)

multiply like terms together

multiplication of same sign gives +, while that of opposite sign gives -

= 2x²-2xy-3x+2xy-2y²-3y+10x-10y-15

collect like terms

= 2x² - 2y² + 7x -13y - 15

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

the correct option is b

step-by-step explanation: