suppose there is a card game where you are dealt a hand of three cards. you have already learned that the total number of three card hands that can be dealt from a deck of 52 cards is:

A. The total number of three-card hands (permutations) that can be made with two aces is 576

B. The actual number of two-ace hands (combinations) you can get from a deck of 52 cards is 288

C. The probability of drawing a three-card hand that includes two aces from a deck of 52 cards is 0.0130

Step-by-step explanation:

A. In order to calculate the total number of three-card hands (permutations) that can be made with two aces we would have to make the following calculation:

total number of three-card hands (permutations) that can be made with two aces=4*3*52

total number of three-card hands (permutations) that can be made with two aces=576.

B. In order to calculate the actual number of two-ace hands (combinations) you can get from a deck of 52 cards we would have to make the following calculation:

actual number of two-ace hands (combinations) you can get from a deck of 52 cards=4C2*48

4C2=4!/2!2!

C2=6

Therefore, actual number of two-ace hands (combinations) you can get from a deck of 52 cards=6*48=288

C. In order to calculate the probability of drawing a three-card hand that includes two aces from a deck of 52 cards we would have to make the following calculation:

probability of drawing a three-card hand that includes two aces from a deck of 52 cards=actual number of two-ace hands (combinations) you can get from a deck of 52 cards/52C3

probability of drawing a three-card hand that includes two aces from a deck of 52 cards=288/22,100

probability of drawing a three-card hand that includes two aces from a deck of 52 cards=0.0130

answer: was that a question or answer?

step-by-step explanation:

answer: 0.64

step-by-step explanation: