A population has a standard deviation of 50. A random sample of 100 items from this population is selected. The sample mean is determined to be 600. At 95% confidence, the margin of error is

Margin of error is 9.8

Step-by-step explanation:

Using the formular for the margin of error

The margin of error = z* (sd/√n)

Where z is the z score for the desired confidence level = 1.96, sd is the population standard deviation = 50 and n is the sample size = 100

Thus

Margin of error = 1.96 (50/√100)

= 1.96 (50/10)

= 1.96 (5)

= 9.8

Margin of error is 9.8

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

square root

step-by-step explanation: