A company rounds its losses to the nearest dollar. The error on each loss is independently and uniformly distributed on [–0.5, 0.5]. If the company rounds 2000 such claims, find the 95th percentile for the sum of the rounding errors.

the 95th percentile for the sum of the rounding errors is 21.236

Step-by-step explanation:

Let consider X to be the rounding errors

Then;

where;

a = -0.5 and b = 0.5

Also;

Since The error on each loss is independently and uniformly distributed

Then;

where;

n = 2000

Mean

Recall:

For 95th percentile or below

From Normal table; Z >   1.645 = 0.05

the 95th percentile for the sum of the rounding errors is 21.236

98 points djdjsi zisksis sjsjsi sisksj sksjdj sksks sjsisj

answer:   y=2x-3

step-by-step explanation: