3) and What is the equation, in point-slope form, of the line that
is perpendicular to the given line and passes through the
point (-4, 3)?
O y-3 = -2(x+4)
Oy-3=-{(x + 4)
y-3 = {(x + 4)
O y-3 = 2(x + 4)

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The given line passes through the points (-4, -3) and (4, 1).

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-4, 3)?

a) y - 3 = -2(x + 4)

b) y - 3= - (x + 4)

c) y - 3 = (x + 4)

d) y - 3 = 2(x + 4)

The equation of the line that is perpendicular to the given line and passes through the point (-4, 3) is

a) y - 3 = -2(x +4)

Step-by-step explanation:

First of all, we will find the slope of the given line.

We are given that the line passes through the points (-4, -3) and (4, 1)

The slope of the equation is given by

Recall that the slopes of two perpendicular lines are negative reciprocals of each other.

So the slope of the other line is

Now we can find the equation of the line that is perpendicular to the given line and passes through the point (-4, 3)

The point-slope form is given by,

Substitute the value of slope and the given point

Therefore, the correct option is (a)

y - 3 = -2(x + 4)

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.