Please help thanks !

point slope form: y-3=(x+2)

slope-intercept form: y=x+

Step-by-step explanation:

so to find point-slope form, you first have to find the slope of the line

--slope == (you have to use the two points shown: (-2,3) and (3,0) to plug in for y1, y2, x1, and x2 to find the slope.)

so your slope is .

Now all you have to do is use one of the points (-2,3) to sub in for y1 and x1 in the point-slope form equation.

Therefore, you get y-3=(x+2) for point-slope form.

Now for slope-intercept form, you already have the slope because you found it to complete the equation for point slope form

slope =

Now slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.

So, far we have y=x+b

the easiet point to use for the x and y values is (3,0)

so, lets substitute: 0=(3)+b, which becomes 0=+b

add to both sides to get b=

Now you have both the slope and the y-intercept so you can now write the line in slope-intercept form.

You get .

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step-by-step explanation: