In a school having 200 students, 120 play football,70 play cricket and 60 play both. The number of students play neither football nor cricket is a)90 b)80 c)70 d)60 (related to functions chapter)

70

Step-by-step explanation:

In a school having 200 students, 120 play football, 70 play cricket and 60 play both. What is the number of students playing neither football nor cricket?

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Well, that 60 is your clue and the key to cracking this.

If 60 do both, then we can subtract that from either football or cricket. Cricket looks easier.

Those playing cricket but not football must be 10, since 70 play cricket in total but 60 do both.

If 120 students play football, and ten more play cricket only, that’s 130 students playing either cricket or football or both. There’s 200 in the school.

200- No.of players = No. of non-players and so 200–130 = 70.

70 of the little bleeders are not playing. Well, I hope they’re being made to do either Rugby or Cross-Country instead. Of course they coul

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The answer is 70.

This problem can be solved with the help of Venn diagram and Sets & Theory Function.

I have solved this sum in my notebook. So by solving the sum we get the following information

Total number of students in school: 200

Students playing football: 120

Students playing cricket: 70

Students playing both cricket and football: 60

Total number of students playing cricket and football: 130

Thus we can conclude that the answer is 70.

Total number of students in school-Total number of students playing cricket and football

i.e. 200–130=70.

Thus the number of students playing neither football nor c

70 play neither football nor cricket.

Total students = 200

70 play cricket and 120 play football.

60 play both football and cricket.

Thereby 70 - 60 = 10 play only cricket.

Similarly, 120 - 60 = 60 play only football.

So total students playing only football and only cricket and both = 60 + 10 + 60 = 130

Thereby students who play neither cricket nor football are = 200 - 130 = 70

THIS CAN BE UNDERSTOOD BEST BY A VENN DIAGRAM.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

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