![cosA=\frac{(b^2+c^2-a^2)}{2bc} \\cos x =(3.5^2+ 3.5^2 -4^2)}/[2(3.5)(3.5)]cos x =0.346939\\x=69.7](/tpl/images/0711/0607/66031.png)
Find the value of
x in the triangle shown below.
...
Answers: 3
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